# The Center-Generated Bidirectional Offset Spiral Proposition  
## —Formalized Geometry of Complete Turns, Positive Thickness, Non-Overlapping, and Spiral Annular Bands

**Author:** Neo.K  
**Version:** v0.1  
**Date:** July 27, 2026  
**Nature of Research:** Geometric Proposition Paper / Formal Foundation Draft  
**Status:** Basic tubular geometry and classification propositions are directly provable; contact saturation and global optimization problems remain to be studied.

---

## Abstract

This paper formalizes a class of planar geometry generated outward from a center, possessing positive thickness, non-overlapping interiors, but allowing boundary contact. Its basic skeleton is a regular curve originating from a center, with its direction continuously rotating with respect to the parameter; it is then simultaneously offset outward and inward along the curve's normal, forming a band-like region with a positive two-dimensional measure.

This paper first clarifies: a total turning angle of $360^\circ$ for a planar curve is insufficient to deduce that the curve is a circle. Only when the curvature is a constant everywhere is a complete $2\pi$ turning unit a circle. When the curve continues to increase its radial scale after completing a full turn, the centerline is no longer a single circle but forms an outwardly expanding spiral.

Let the centerline be

$$
\gamma:[0,L]\to\mathbb R^2,
$$

Given a thickness radius $\rho>0$, its bidirectional normal offset band is defined as

$$
S_\rho(\gamma)
=
\left\{
\gamma(s)+tN(s):
0\le s\le L,\;
-\rho\le t\le\rho
\right\}.
$$

If the normal parameterization is injective in the interior, the interiors of different layers do not overlap; if only boundary tangency or joining is allowed, it can be viewed as a limiting case of contact saturation. For a valid open curve, the area of the normal band without end caps is

$$
\mu_2(S_\rho(\gamma))=2\rho L,
$$

After adding semicircular caps at both ends, the area of the complete tubular neighborhood is

$$
\mu_2(T_\rho(\gamma))
=
2\rho L+\pi\rho^2.
$$

This paper proposes the "Center-Generated Bidirectional Offset Spiral Proposition": if the centerline starts from the center, its radial scale does not regress, it maintains a positive radial increment after completing a full turn, and it satisfies the non-overlapping interior condition, then its global geometry is a spiral centerline; after bidirectional offsetting, it forms a spiral annular band. If the radial increment is zero, it degenerates into a circle and its annulus; if the inward offset fills the central hole, it degenerates into a disk or a spiral-generated disk.

This paper also distinguishes between separated, contact, and overlapping spiral bands, explaining that the radial pitch of an Archimedean spiral can only serve as a proxy for layer spacing, whereas the precise non-overlapping condition should be controlled by the curve's reach.

**Keywords:** Center generation, bidirectional offset, spiral annular band, complete turn, positive thickness, tubular neighborhood, reach, curvature, non-overlapping, boundary contact

---

# 1. Starting Point of the Problem

Consider a "crooked line" in a two-dimensional plane. We require:

1. It starts from a certain center position;
2. It continuously extends outward;
3. It can turn;
4. The interiors of different parts cannot overlap;
5. Boundaries can be tangent, joined, or share contact points;
6. The final geometry has a positive two-dimensional measure;
7. The centerline is simultaneously offset inward and outward.

This set of conditions does not describe an ordinary zero-thickness curve, but rather describes:

$$
\boxed{
\text{A center curve and its positive-thickness normal band}
}.
$$

If the centerline only completes one full turn and the radius is fixed, the most natural shape is a circle.

If it continues to generate outward after completing one full turn, the most natural global shape is a spiral.

---

# 2. Basic Space and Measure

Let

$$
\mathbb R^2
$$

be the two-dimensional Euclidean plane, and the two-dimensional Lebesgue measure be denoted as

$$
\mu_2.
$$

Let

$$
\gamma:[0,L]\to\mathbb R^2
$$

be a regular curve of finite length that is piecewise $C^2$.

If $\gamma$ is merely an ordinary rectifiable curve, then

$$
\mu_2(\gamma([0,L]))=0.
$$

Therefore, a "non-zero minimum measure" cannot be provided by the pure centerline itself, but requires the introduction of positive thickness.

---

# 3. Positive Thickness and Bidirectional Normal Offset

Assume $\gamma$ is parameterized by arc length:

$$
\|\gamma'(s)\|=1.
$$

Define the unit tangent vector:

$$
T(s)=\gamma'(s).
$$

Select the unit normal vector:

$$
N(s)=R_{\pi/2}T(s).
$$

Given the thickness radius

$$
\rho>0,
$$

define the normal parameterization:

$$
F_\rho(s,t)
=
\gamma(s)+tN(s),
\qquad
(s,t)\in[0,L]\times[-\rho,\rho].
$$

Its image set

$$
\boxed{
S_\rho(\gamma)
=
F_\rho
\left(
[0,L]\times[-\rho,\rho]
\right)
}
$$

is called the bidirectional normal offset band of the center curve.

Its two local boundaries are

$$
\gamma_+(s)
=
\gamma(s)+\rho N(s),
$$

$$
\gamma_-(s)
=
\gamma(s)-\rho N(s).
$$

---

# 4. Complete Tubular Neighborhood

The normal offset band $S_\rho(\gamma)$ does not include the circular caps extending in the direction of the curve's endpoints.

If we take the Minkowski sum of the curve and a closed disk $B_\rho$ of radius $\rho$, defining:

$$
\boxed{
T_\rho(\gamma)
=
\gamma([0,L])\oplus B_\rho
}
$$

Then $T_\rho(\gamma)$ is the complete tubular neighborhood.

For an open curve, it equals:

$$
\text{Normal band}
+
\text{Two semicircular end caps}.
$$

This paper will:

- Call $S_\rho(\gamma)$ the offset band without end caps;
- Call $T_\rho(\gamma)$ the complete thickened region.

---

# 5. Non-Overlapping and Allowed Contact

## Definition 5.1: Strictly Non-Overlapping

If

$$
F_\rho:
[0,L]\times(-\rho,\rho)
\to\mathbb R^2
$$

is injective, the normal band is said to be strictly non-overlapping in its interior.

That is, if

$$
F_\rho(s,t)=F_\rho(s',t'),
$$

and

$$
|t|<\rho,
\qquad
|t'|<\rho,
$$

then we must have

$$
s=s',
\qquad
t=t'.
$$

## Definition 5.2: Boundary Contact Allowed

It is allowed for different parameter points

$$
(s,t)\ne(s',t')
$$

such that

$$
F_\rho(s,t)=F_\rho(s',t'),
$$

but this can only occur when

$$
|t|=\rho
\quad\text{or}\quad
|t'|=\rho.
$$

Therefore

$$
\operatorname{Int}S_\rho(\gamma)
$$

must not self-overlap, but

$$
\partial S_\rho(\gamma)
$$

can be tangent or joined.

---

# 6. Reach Condition

For a closed set $X\subset\mathbb R^2$, its reach is defined as: the maximum radius of a unique projection neighborhood such that all points sufficiently close to $X$ have a unique nearest point.

For the center curve $\gamma$, if

$$
\operatorname{reach}(\gamma)>\rho,
$$

then:

1. Points with a distance to the centerline less than $\rho$ have a unique nearest center point;
2. The normal parameterization remains injective within thickness $\rho$;
3. The interior of the normal band does not overlap;
4. The local radius of curvature is greater than $\rho$.

Therefore

$$
\boxed{
\operatorname{reach}(\gamma)>\rho
}
$$

is the standard strictly valid condition adopted in this paper.

The contact-saturated boundary is written as

$$
\boxed{
\operatorname{reach}(\gamma)=\rho
}.
$$

In this case, the normal band may experience tangency at the boundary for the first time, but the interior still has not produced any positive-area overlap.

---

# 7. Curvature and Complete Turn

Let the tangential angle be

$$
\theta(s),
$$

such that

$$
T(s)
=
(\cos\theta(s),\sin\theta(s)).
$$

The curvature is

$$
\kappa(s)=\theta'(s).
$$

The total turn of the curve over the interval $[a,b]$ is

$$
\Delta\theta
=
\theta(b)-\theta(a)
=
\int_a^b\kappa(s)\,ds.
$$

One complete directed turn is

$$
\Delta\theta=2\pi.
$$

---

# 8. Total Turn of $2\pi$ Does Not Equal a Circle

We must distinguish between:

$$
\int\kappa\,ds=2\pi
$$

and

$$
\kappa(s)\equiv\frac1R.
$$

The former merely indicates that the total tangential rotation is $360^\circ$.

Many non-circular simple closed convex curves also satisfy a total turn of $2\pi$, for example:

- Ellipses;
- Non-uniform convex ovals;
- Smooth irregular convex curves.

Therefore

$$
\boxed{
\text{Total turn of }2\pi
\not\Rightarrow
\text{Curve is a circle}
}.
$$

---

# 9. Circle Generation Theorem

## Theorem 9.1: Constant Curvature Complete Turning Unit

Let $\gamma$ be an arc-length parameterized curve satisfying

$$
\kappa(s)\equiv\frac1R,
\qquad
R>0,
$$

and

$$
b-a=2\pi R.
$$

on some interval $[a,b]$.

Then this curve segment is a complete circle of radius $R$, up to a planar rigid body motion.

### Proof

From

$$
\theta'(s)=\frac1R,
$$

we obtain

$$
\theta(s)
=
\theta(a)+\frac{s-a}{R}.
$$

Integrating again

$$
\gamma'(s)
=
(\cos\theta(s),\sin\theta(s)),
$$

yields

$$
\gamma(s)
=
c+
R
\left(
\sin\theta(s),
-\cos\theta(s)
\right)
$$

which holds for some fixed point $c$.

Therefore

$$
\|\gamma(s)-c\|=R.
$$

Moreover, since

$$
\theta(b)-\theta(a)=2\pi,
$$

the segment completes exactly one full loop. Q.E.D.

## Corollary 9.2

In the geometric language of this paper:

$$
\boxed{
\text{A circle is a complete }360^\circ\text{ turning unit with constant curvature}
}.
$$

---

# 10. Center Generation Condition

"Generated outward from the center" can be expressed using polar coordinates.

Let

$$
\gamma(\vartheta)
=
r(\vartheta)
(\cos\vartheta,\sin\vartheta),
$$

where

$$
0\le\vartheta\le\Theta.
$$

Require

$$
r(0)=0,
$$

and

$$
r'(\vartheta)\ge0.
$$

This means that as the polar angle increases, the curve will not regress to a smaller radius along the same ray.

More generally, if arc-length parameterization is used, we can require

$$
\frac{d}{ds}
\|\gamma(s)\|
\ge0
$$

to hold where differentiable.

This paper refers to this type of condition as

$$
\boxed{
\text{Radially non-degenerate center generation condition}
}.
$$

---

# 11. Radial Increment Per Loop

Define the radial increment after one complete loop:

$$
\Delta_{2\pi}r(\vartheta)
=
r(\vartheta+2\pi)-r(\vartheta).
$$

We can distinguish:

## Zero Radial Increment

$$
\Delta_{2\pi}r(\vartheta)=0.
$$

## Positive Radial Increment

$$
\Delta_{2\pi}r(\vartheta)>0.
$$

Zero radial increment means the curve returns to the same radius after each full turn.

Positive radial increment means the curve moves to an outer layer after completing each loop.

---

# 12. Zero Increment Degenerates to a Circle

## Proposition 12.1

If

$$
r'(\vartheta)\ge0
$$

and for all applicable $\vartheta$

$$
r(\vartheta+2\pi)=r(\vartheta),
$$

then $r$ is constant over each complete period.

If we further require the curve to complete a full turn without repeated winding, the centerline degenerates into a circle:

$$
\gamma(\vartheta)
=
R(\cos\vartheta,\sin\vartheta).
$$

### Proof

By monotonic non-decrease:

$$
r(\vartheta)
\le
r(\vartheta+\eta)
\le
r(\vartheta+2\pi)
$$

holds for

$$
0\le\eta\le2\pi.
$$

But the period endpoints are equal:

$$
r(\vartheta+2\pi)=r(\vartheta).
$$

Hence all intermediate values are equal. Q.E.D.

---

# 13. Bidirectional Offset of a Circle

If the centerline is a circle of radius $R$:

$$
\gamma(\vartheta)
=
R(\cos\vartheta,\sin\vartheta),
$$

then its inner and outer offset boundaries are:

$$
\gamma_+(\vartheta)
=
(R+\rho)
(\cos\vartheta,\sin\vartheta),
$$

$$
\gamma_-(\vartheta)
=
(R-\rho)
(\cos\vartheta,\sin\vartheta).
$$

If

$$
0<\rho<R,
$$

then the offset region is an annulus:

$$
\boxed{
A_{R,\rho}
=
\left\{
x\in\mathbb R^2:
R-\rho\le\|x\|\le R+\rho
\right\}
}.
$$

Its area is:

$$
\mu_2(A_{R,\rho})
=
\pi(R+\rho)^2
-
\pi(R-\rho)^2
=
4\pi R\rho.
$$

Since the circumference of the circle is

$$
L=2\pi R,
$$

it can also be written as

$$
\mu_2(A_{R,\rho})
=
2\rho L.
$$

## Degeneration to a Disk

If

$$
\rho\ge R,
$$

then the inward offset reaches or exceeds the center.

In this case, the central hole of the annulus disappears, and the complete thickened region becomes a disk of radius

$$
R+\rho
$$

:

$$
\boxed{
D_{R+\rho}
=
\left\{
x:
\|x\|\le R+\rho
\right\}
}.
$$

---

# 14. Positive Increment Generates a Spiral

## Proposition 14.1: Positive Radial Increment Excludes a Single Circle

If there exists some $\vartheta$ such that

$$
r(\vartheta+2\pi)
>
r(\vartheta),
$$

then the centerline cannot be a single fixed-radius circle.

If this positive increment persists, the centerline forms an outwardly expanding spiral curve.

### Proof

A single circle must satisfy

$$
r(\vartheta)\equiv R.
$$

Therefore

$$
r(\vartheta+2\pi)-r(\vartheta)=0.
$$

which contradicts the positive increment condition. Q.E.D.

---

# 15. Center-Generated Spiral

This paper defines a center-generated spiral as a polar coordinate curve

$$
\gamma(\vartheta)
=
r(\vartheta)
(\cos\vartheta,\sin\vartheta),
$$

satisfying:

1. $r(0)=0$;
2. $r'(\vartheta)\ge0$;
3. A complete turn exists;
4. At least some complete periods have a positive radial increment;
5. The curve is regular;
6. After thickening, it satisfies the non-overlapping interior condition.

This definition does not require

$$
r(\vartheta)
$$

to be a linear function.

Therefore it includes:

- Archimedean spirals;
- Non-uniform pitch spirals;
- Variable curvature spirals;
- Piecewise smooth spirals;
- Curvature-concentrated spirals.

---

# 16. Archimedean Spiral

If

$$
r'(\vartheta)=b>0,
$$

then

$$
r(\vartheta)=r_0+b\vartheta.
$$

When starting from the center

$$
r_0=0,
$$

hence

$$
\boxed{
r(\vartheta)=b\vartheta
}.
$$

After completing each loop, its radial difference along the same ray is

$$
p
=
r(\vartheta+2\pi)-r(\vartheta)
=
2\pi b.
$$

where $p$ is called the radial pitch.

---

# 17. Radial Pitch is Not a Precise Non-Overlapping Condition

For an Archimedean spiral, the radial distance between the centerlines of two adjacent loops in the same polar angle direction is indeed

$$
p=2\pi b.
$$

Thus, a common approximate classification is:

$$
p>2\rho
$$

layer separation when,

$$
p=2\rho
$$

layer contact when,

$$
p<2\rho
$$

layer overlap when.

But it must be noted:

> The normal offset direction is generally not equal to the pure radial direction.

Therefore

$$
p\ge2\rho
$$

cannot replace the precise global non-overlapping criterion in the general case.

The precise condition should still be written as

$$
\boxed{
\operatorname{reach}(\gamma)\ge\rho
}.
$$

Radial pitch is merely a convenient preliminary proxy.

---

# 18. The Center-Generated Bidirectional Offset Spiral Proposition

## Main Proposition

Let

$$
\gamma(\vartheta)
=
r(\vartheta)
(\cos\vartheta,\sin\vartheta)
$$

be a piecewise $C^2$ regular curve, satisfying:

1. Center origin:
   $$
   r(0)=0;
   $$

2. Radially non-degenerate:
   $$
   r'(\vartheta)\ge0;
   $$

3. Complete turn exists:
   $$
   \Theta\ge2\pi;
   $$

4. The curve can continue to extend after completing one loop;

5. Given thickness:
   $$
   \rho>0;
   $$

6. Non-overlapping interior of the normal band:
   $$
   \operatorname{reach}(\gamma)\ge\rho;
   $$

7. Boundaries can contact, but must not produce positive-area interior overlap.

Then we have:

### Case A: Zero Periodic Radial Increment

If

$$
r(\vartheta+2\pi)=r(\vartheta)
$$

holds for all applicable $\vartheta$, then the centerline degenerates into a fixed-radius complete turning curve; under constant curvature conditions, it is a circle.

Its bidirectional offset geometry is an

$$
\boxed{
\text{Annulus}
}
$$

or, when the inner hole disappears, a

$$
\boxed{
\text{Disk}
}.
$$

### Case B: Positive Periodic Radial Increment

If there exists

$$
\Delta_{2\pi}r(\vartheta)>0,
$$

then the centerline is not a single circle, but an outwardly expanding spiral curve.

Its bidirectional normal offset region is a

$$
\boxed{
\text{Center-generated bidirectional offset spiral annular band}
}.
$$

### Case C: Contact Saturation

If

$$
\operatorname{reach}(\gamma)=\rho,
$$

and tangency only occurs for the first time at the boundary, it forms a

$$
\boxed{
\text{Contact spiral annular band}
}.
$$

If the contact sequence further encloses all internal gaps, its overall closure can be viewed as a

$$
\boxed{
\text{Spiral-generated disk}
}.
$$

---

# 19. Precise Definition of the Spiral Annular Band

## Definition 19.1

For a center-generated spiral $\gamma$, define

$$
\boxed{
\mathcal S_{\gamma,\rho}
=
S_\rho(\gamma)
}
$$

as the center-generated bidirectional offset spiral annular band.

If end caps are added

$$
\boxed{
\mathcal T_{\gamma,\rho}
=
T_\rho(\gamma)
}
$$

it is called the complete spiral tubular region.

---

# 20. Geometric Classification

## 20.1 Strictly Separated Type

If

$$
\operatorname{reach}(\gamma)>\rho,
$$

then both the interiors and boundaries of different normal fibers maintain a positive separation distance.

It is called a

$$
\boxed{
\text{Strictly separated spiral annular band}
}.
$$

## 20.2 Contact Type

If

$$
\operatorname{reach}(\gamma)=\rho,
$$

and only boundary contact occurs, it is called a

$$
\boxed{
\text{Contact spiral annular band}
}.
$$

## 20.3 Overlapping Type

If

$$
\operatorname{reach}(\gamma)<\rho,
$$

then there exist points in the positive-thickness neighborhood with multiple nearest center points, and the normal band may exhibit interior overlap.

In this case, it is called an

$$
\boxed{
\text{Overlapping spiral band}
}.
$$

It does not satisfy the non-overlapping interior condition of the main proposition of this paper.

---

# 21. Area Formula

## Theorem 21.1: Area of the Offset Band Without End Caps

If

$$
\operatorname{reach}(\gamma)>\rho,
$$

then

$$
\boxed{
\mu_2(S_\rho(\gamma))
=
2\rho L
}.
$$

### Proof

From the Frenet formulas

$$
N'(s)=-\kappa(s)T(s),
$$

we obtain

$$
\partial_sF_\rho
=
(1-t\kappa(s))T(s),
$$

$$
\partial_tF_\rho=N(s).
$$

The Jacobian is

$$
J(s,t)
=
1-t\kappa(s).
$$

Therefore

$$
\begin{aligned}
\mu_2(S_\rho(\gamma))
&=
\int_0^L
\int_{-\rho}^{\rho}
(1-t\kappa(s))
\,dt\,ds\\
&=
\int_0^L2\rho\,ds\\
&=
2\rho L.
\end{aligned}
$$

Q.E.D.

## Corollary 21.2: Tubular Area of the Complete Open Curve

After adding semicircular caps at both ends

$$
\boxed{
\mu_2(T_\rho(\gamma))
=
2\rho L+\pi\rho^2
}.
$$

## Corollary 21.3: Non-Zero Area

As long as

$$
L>0,
\qquad
\rho>0,
$$

we have

$$
\boxed{
\mu_2(S_\rho(\gamma))>0
}.
$$

Therefore, the positive thickness condition ensures the geometry is no longer a two-dimensional zero-measure pure line.

---

# 22. Area Conservation and Shape Differences

For all valid non-overlapping centerlines of the same length and same thickness

$$
\mu_2(S_\rho(\gamma))
=
2\rho L.
$$

So

$$
\boxed{
\text{Annuli, spiral annular bands, and other valid normal bands can have the same total area}
}.
$$

But they may still have different:

- Curvature distributions;
- Support functions;
- Convex hulls;
- Diameters;
- Directional widths;
- Topological contact structures;
- Container embedding difficulties.

Therefore

$$
\boxed{
\text{Same total amount}
\not\Rightarrow
\text{Same geometry}
}.
$$

---

# 23. Local Circle and Global Spiral

This paper distinguishes between the following two statements.

## Local Complete Turn Language

If a certain turning unit has constant curvature, then

$$
\boxed{
\text{This unit is a circle}
}.
$$

## Global Extrapolation Language

If the radial scale still increases after each complete turn, then

$$
\boxed{
\text{The globally connected shape is a spiral}
}.
$$

Therefore

$$
\boxed{
\text{A circle is a local constant-curvature complete turning unit;
a spiral is the global connection language of multiple outward turning units}
}.
$$

---

# 24. Spiral-Generated Disk

"Spiral annular band" and "spiral-generated disk" must be distinguished.

## Spiral Annular Band

If gaps still exist between the thickened spiral layers, the region is not a complete disk.

## Spiral-Generated Disk

If:

1. The layers are in continuous contact at the boundaries;
2. No positive-area overlap exists;
3. No open-set gaps are left between the center and the outermost layer;
4. The closure of the resulting region is a disk-like set;

Then it is called a

$$
\boxed{
\text{Spiral-generated disk}
}.
$$

This is a global filling condition and cannot be deduced solely from a single pitch equation.

---

# 25. Topological Classification

For a strictly separated finite open spiral band, excluding end caps, its parameter domain is

$$
[0,L]\times[-\rho,\rho].
$$

Under interior injectivity, its topological type is equivalent to a closed rectangle

$$
\boxed{
D^2
}.
$$

For a closed circular centerline, its annular topological type is

$$
\boxed{
S^1\times[0,1]
}.
$$

If the central hole disappears, the topological type becomes

$$
\boxed{
D^2
}.
$$

So

$$
\text{Annulus}
\quad\text{and}\quad
\text{Open spiral band}
$$

Even if both visually have "wrapping," their topological origins can still be different.

---

# 26. Relationship with Pure Circle Language

If the geometric language stipulates:

> All complete $360^\circ$ turns must be completed with constant curvature,

Then each independent complete turning unit is a circle.

But if the centers or radii of these turning units continuously change, after joining them continuously, the whole is no longer a single circle.

Therefore, the correct form is

$$
\boxed{
\text{Each fixed-scale complete turning unit can be a circle;
the multi-scale continuously extrapolated whole can be a spiral}
}.
$$

It cannot be directly written as

$$
\text{All geometries with a total turning angle of }360^\circ\text{ are circles}.
$$

---

# 27. Main Corollaries

## Corollary A: Necessity of Positive Thickness

If a positive two-dimensional measure is required, one must study

$$
S_\rho(\gamma)
\quad\text{or}\quad
T_\rho(\gamma),
$$

rather than the pure centerline.

## Corollary B: Annulus Degeneration

If the radial increment is zero and the curvature is constant, the centerline is a circle, and the bidirectional offset is an annulus.

## Corollary C: Spiral Annular Band Generation

If there is still a positive radial increment after completing a full turn, the global centerline is not a circle, but a spiral curve; its bidirectional offset is a spiral annular band.

## Corollary D: Contact Saturation

The precise boundary condition for a geometry that "can contact but cannot overlap" is

$$
\operatorname{reach}(\gamma)=\rho.
$$

## Corollary E: Area is Independent of Curvature Distribution

As long as the normal band is valid and non-self-intersecting

$$
\mu_2(S_\rho(\gamma))=2\rho L.
$$

Therefore, curvature affects the shape, but does not affect the total area of the band without end caps.

---

# 28. New Research Problems

## Problem 28.1: Existence of Contact-Saturated Spirals

Given

$$
L,\rho,\Theta,
$$

does there exist a center-generated spiral satisfying

$$
\operatorname{reach}(\gamma)=\rho
$$

and completing a specified total turn?

## Problem 28.2: Precise Conditions for Spiral-Generated Disks

What conditions can guarantee that

$$
\overline{S_\rho(\gamma)}
$$

is a disk-like set, and there are no open-set gaps from the center to the outermost boundary?

## Problem 28.3: Minimum Enclosing Circle

Under fixed

$$
L,\rho,\Theta
$$

which valid center-generated spiral minimizes the radius of the minimum enclosing circle of its bidirectional offset band?

## Problem 28.4: Maximum Support Pressure

Under fixed length and thickness, which curvature distribution makes

$$
h_{T_\rho(\gamma)}(u)
$$

the most difficult to be mutually accommodated in certain directions?

## Problem 28.5: Constant Curvature and Curvature Concentration

Is the most effective extrapolated geometry:

- Constant curvature spiral;
- Piecewise constant curvature;
- Finite-width curvature concentration layer;
- Contact-saturated variable curvature spiral?

---

# 29. Formalization Interface

If proceeding to Lean, Coq, or other formal systems in the future, it can be processed in the following order.

## Layer 1: Curve and Frenet Frame

Formalize

$$
T=\gamma',
\qquad
N=R_{\pi/2}T,
\qquad
T'=\kappa N.
$$

## Layer 2: Normal Mapping

Formalize

$$
F_\rho(s,t)=\gamma(s)+tN(s).
$$

## Layer 3: Jacobian

Prove

$$
\det
(\partial_sF_\rho,\partial_tF_\rho)
=
1-t\kappa(s).
$$

## Layer 4: Area Formula

Prove

$$
\mu_2(S_\rho(\gamma))=2\rho L.
$$

under the conditions of injectivity and positive Jacobian.

## Layer 5: Constant Curvature Circle

Prove that

$$
\kappa\equiv1/R
$$

and complete arc length

$$
L=2\pi R
$$

deduce a circle.

## Layer 6: Polar Coordinate Classification

Formalize

$$
r'(\vartheta)\ge0
$$

and periodic increment

$$
r(\vartheta+2\pi)-r(\vartheta).
$$

---

# 30. Limitations

This paper does not prove:

1. All center-generated curves must be Archimedean spirals;
2. The radial pitch $2\pi b$ is the precise layer spacing for general normal bands;
3. $\operatorname{reach}(\gamma)=\rho$ necessarily fills the entire interior completely;
4. A contact spiral definitely forms a disk;
5. A specific spiral is the optimal solution for area, enclosing circle, or universal accommodation problems;
6. All curves with a total turning angle of $2\pi$ are circles;
7. This paper has solved the Kakeya problem, Moser's worm problem, or other universal covering problems.

What this paper accomplishes is:

- Precise definition of the geometric objects;
- Logical classification of circles and spirals;
- Reach formulation of non-overlapping and contact;
- Positive area formula for bidirectional offset bands;
- Fundamental propositions required for subsequent bridging theories.

---

# 31. Conclusion

This paper formalizes the center-generated bidirectional offset spiral.

Its basic geometric chain is:

$$
\boxed{
\text{Center origin}
\longrightarrow
\text{Continuous direction rotation}
\longrightarrow
\text{Complete }360^\circ
\longrightarrow
\text{Still extending outward}
\longrightarrow
\text{Spiral centerline}
\longrightarrow
\text{Bidirectional normal offset}
\longrightarrow
\text{Spiral annular band}
}.
$$

If there is no radial increment, and a constant curvature condition is added, then

$$
\boxed{
\text{The centerline is a circle, and the offset region is an annulus or a disk}
}.
$$

If it has a positive radial increment, then

$$
\boxed{
\text{The centerline is a spiral curve, and the offset region is a spiral annular band}
}.
$$

If

$$
\operatorname{reach}(\gamma)=\rho,
$$

then

$$
\boxed{
\text{Forms a contact-saturated state that allows boundary contact but not interior overlap}
}.
$$

Its area under valid conditions is

$$
\boxed{
\mu_2(S_\rho(\gamma))=2\rho L
}.
$$

Therefore, the core of this proposition can be condensed as:

$$
\boxed{
\text{A circle is a fixed-scale constant-curvature complete turning unit;
a spiral is the global geometry of a complete turning unit continuously extending outward;
bidirectional offsetting transforms a zero-area centerline into a positive-area spiral annular band}
}.
$$

---

# Appendix A: Table of Symbols

| Symbol | Meaning |
|---|---|
| $\gamma$ | Center-generated curve |
| $L$ | Length of the center curve |
| $T(s)$ | Unit tangent vector |
| $N(s)$ | Unit normal vector |
| $\theta(s)$ | Tangential angle |
| $\kappa(s)$ | Curvature |
| $\rho$ | Thickness radius |
| $F_\rho(s,t)$ | Normal parameterization |
| $S_\rho(\gamma)$ | Bidirectional offset band without end caps |
| $T_\rho(\gamma)$ | Complete tubular neighborhood |
| $r(\vartheta)$ | Polar coordinate radius function |
| $\Delta_{2\pi}r$ | Radial increment after one loop |
| $\operatorname{reach}(\gamma)$ | Tubular radius of unique nearest point |
| $p$ | Radial pitch of the Archimedean spiral |

---

# Appendix B: Shortest Proposition Version

Let $\gamma$ be a planar regular curve starting from the center, with a non-decreasing radial scale, and completing at least one full turn. Take its bidirectional normal offset with a thickness radius $\rho>0$, requiring the interior of the normal band to be non-overlapping while boundaries can contact.

Then:

$$
\Delta_{2\pi}r=0
$$

and when curvature is constant, the centerline is a circle, and after thickening it is an annulus or a disk;

$$
\Delta_{2\pi}r>0
$$

when, the centerline is an outwardly generated spiral curve, and after thickening it is a center-generated bidirectional offset spiral annular band;

$$
\operatorname{reach}(\gamma)=\rho
$$

describes the contact-saturated state where boundaries exactly contact;

Under strictly valid tubular conditions:

$$
\mu_2(S_\rho(\gamma))=2\rho L.
$$