# NS × X Integral × 24/72 Paradigm Practice
## Round 12 — Pure Continuous Critical Dual Geometry / Cancellation-Tradeoff Route

- Date:  2026-08-16
- Version:  v0.1
- Status:  Proof-Route Experiment / Continuous-Only Critical-Dual Branch
- canonical source: UTF-8 Markdown
- canonical math delimiters: inline `$...$`; display `$$...$$`
- Previous round:  `NS_X72_Round11_PureContinuous_DeterministicFunctionalResummation_DualAdjoint_v0.1_2026-08-16.md`
- This round's objective:  Investigate whether the backward matched dual propagator from Round 11 can recover the exact contraction of $L^2$ in scale-critical dual spaces. The main tests are on $L^{3/2}$ and $\dot H^{-1/2}$, to determine if there is a structural tradeoff among the Leray projection, transport skewness, and the critical metric.
- Non-claims:  This document only provides a restricted no-go for two natural classes of critical dual geometry and two broad metric subfamilies. It does not claim that all possible nonlinear/nonlocal critical dual geometries cannot be contractive.

---

# 0. Round 11 handoff

Round 11 resummed the deterministic interaction-order hierarchy:

$$
3\to4\to5\to\cdots
$$

into the generating functional:

$$
\mathcal Z[\varphi,t]
=
e^{\langle\varphi,u(t)\rangle},
$$

whose exact functional PDE only requires second-order functional derivatives.

Therefore, the interaction order is not an essential discreteness witness.

The same round yielded the matched backward dual equation:

$$
\boxed{
\partial_t\varphi
+
\nu\Delta\varphi
+
P[(u\cdot\nabla)\varphi]
=
0,
}
\tag{0.1}
$$

and:

$$
\boxed{
\frac d{dt}
\langle
\varphi(t),u(t)
\rangle
=
0.
}
\tag{0.2}
$$

If:

$$
\varphi(T)=\varphi_T,
$$

then:

$$
\boxed{
\langle
\varphi_T,u(T)
\rangle
=
\langle
\varphi(0),u_0
\rangle.
}
\tag{0.3}
$$

Round 11 obtained a backward dual contraction in $L^2$.

This round asks:

$$
\boxed{
\text{Does critical dual geometry also have the same contraction?}
}
$$

---

# 1. Forward backward-time formulation

Let:

$$
\sigma=T-t,
$$

$$
\psi(\sigma,x)
=
\varphi(T-\sigma,x),
$$

and:

$$
U(\sigma,x)
=
u(T-\sigma,x).
$$

Then:

$$
\boxed{
\partial_\sigma\psi
=
\nu\Delta\psi
+
P[(U\cdot\nabla)\psi].
}
\tag{1.1}
$$

where:

$$
\nabla\cdot U=0,
$$

and if:

$$
\nabla\cdot\psi(0)=0,
$$

then:

$$
\nabla\cdot\psi(\sigma)=0.
$$

To simplify notation, we write below:

$$
T_U
=
U\cdot\nabla.
$$

---

# 2. Dual critical scaling

Navier–Stokes scaling:

$$
u_\lambda(x,t)
=
\lambda
u(\lambda x,\lambda^2t).
$$

To keep the pairing:

$$
\langle
\psi,u
\rangle
$$

scale-invariant, the dual field must scale as:

$$
\boxed{
\psi_\lambda(x,t)
=
\lambda^2
\psi(\lambda x,\lambda^2t).
}
\tag{2.1}
$$

For:

$$
L^p
$$

we have:

$$
\|\psi_\lambda\|_{L^p}
=
\lambda^{2-\frac3p}
\|\psi\|_{L^p}.
$$

Thus, the critical dual exponent is:

$$
\boxed{
p=\frac32.
}
\tag{2.2}
$$

For homogeneous Sobolev spaces:

$$
\|\psi_\lambda\|_{\dot H^s}
=
\lambda^{s+\frac12}
\|\psi\|_{\dot H^s}.
$$

Thus, the critical Hilbert dual is:

$$
\boxed{
s=-\frac12.
}
\tag{2.3}
$$

Therefore, the two natural critical targets for this round are:

$$
\boxed{
L^{3/2}
}
$$

and:

$$
\boxed{
\dot H^{-1/2}.
}
$$

---

# 3. Why $L^2$ contracts exactly

First, recall:

$$
\frac12
\frac d{d\sigma}
\|\psi\|_2^2
=
\nu
\langle\Delta\psi,\psi\rangle
+
\langle
P T_U\psi,\psi
\rangle.
$$

Since:

$$
P=P^\ast=P^2
$$

and:

$$
P\psi=\psi,
$$

we have:

$$
\langle
P T_U\psi,\psi
\rangle
=
\langle
T_U\psi,\psi
\rangle.
$$

Furthermore, from:

$$
\nabla\cdot U=0,
$$

$$
\langle
T_U\psi,\psi
\rangle
=
0.
$$

Therefore:

$$
\boxed{
\frac12
\frac d{d\sigma}
\|\psi\|_2^2
+
\nu
\|\nabla\psi\|_2^2
=
0.
}
\tag{3.1}
$$

The $L^2$ exact contraction simultaneously uses two structures:

$$
\boxed{
\text{Projection Compatibility}
+
\text{Transport Skewness}.
}
\tag{3.2}
$$

---

# 4. Critical local route: $L^{3/2}$

More generally, let:

$$
1<p<\infty.
$$

Define the norm gradient:

$$
\boxed{
J_p(\psi)
=
|\psi|^{p-2}\psi.
}
\tag{4.1}
$$

Pairing with (1.1):

$$
\boxed{
\frac1p
\frac d{d\sigma}
\|\psi\|_p^p
+
\nu
\mathfrak D_p(\psi)
=
\left\langle
P T_U\psi,
J_p(\psi)
\right\rangle,
}
\tag{4.2}
$$

where:

$$
\boxed{
\mathfrak D_p(\psi)
=
-
\langle
\Delta\psi,
J_p(\psi)
\rangle
\ge0.
}
\tag{4.3}
$$

The raw transport still has an exact chain-rule cancellation:

$$
\boxed{
\langle
T_U\psi,
J_p(\psi)
\rangle
=
\frac1p
\int
U\cdot\nabla
|\psi|^p
dx
=
0.
}
\tag{4.4}
$$

Thus, the local $L^p$ geometry fully preserves the transport cancellation.

---

# 5. The Leray-projection defect

Using:

$$
P=P^\ast,
$$

we have:

$$
\langle
P T_U\psi,
J_p
\rangle
=
\langle
T_U\psi,
P J_p
\rangle.
$$

Subtracting (4.4):

$$
\boxed{
\frac1p
\frac d{d\sigma}
\|\psi\|_p^p
+
\nu
\mathfrak D_p(\psi)
=
\mathfrak P_p[U,\psi],
}
\tag{5.1}
$$

where:

$$
\boxed{
\mathfrak P_p[U,\psi]
=
\left\langle
T_U\psi,
(P-I)J_p(\psi)
\right\rangle.
}
\tag{5.2}
$$

This is the exact Leray-projection defect.

If we write:

$$
P-I
=
\nabla(-\Delta)^{-1}\operatorname{div},
$$

then:

$$
\boxed{
\mathfrak P_p
=
\left\langle
T_U\psi,
\nabla(-\Delta)^{-1}
\operatorname{div}
J_p(\psi)
\right\rangle.
}
\tag{5.3}
$$

Therefore, the issue is not the raw transport.

Rather, it is:

$$
\boxed{
J_p(\psi)
\text{ generally leaves the divergence-free tangent space}.
}
$$

---

# 6. Why $p=2$ is exceptional

When:

$$
p=2,
$$

we have:

$$
J_2(\psi)=\psi.
$$

If:

$$
\nabla\cdot\psi=0,
$$

then:

$$
(P-I)J_2(\psi)=0.
$$

Thus:

$$
\mathfrak P_2=0.
$$

But for:

$$
p\neq2,
$$

$$
J_p(\psi)
=
|\psi|^{p-2}\psi
$$

is generally no longer divergence-free.

In fact:

$$
\boxed{
\operatorname{div}
J_p(\psi)
=
(p-2)
|\psi|^{p-3}
\psi\cdot\nabla|\psi|
}
\tag{6.1}
$$

where:

$$
\psi\neq0
$$

holds.

So unless:

$$
p=2
$$

or the field possesses additional special geometry,

the projection defect does not automatically vanish.

For the critical:

$$
p=\frac32,
$$

we obtain:

$$
\boxed{
\frac23
\frac d{d\sigma}
\|\psi\|_{3/2}^{3/2}
+
\nu
\mathfrak D_{3/2}(\psi)
=
\mathfrak P_{3/2}[U,\psi].
}
\tag{6.2}
$$

Therefore:

$$
\boxed{
L^{3/2}
\text{ keeps chain-rule transport cancellation but loses projection compatibility}.
}
\tag{6.3}
$$

---

# 7. Restricted local-metric uniqueness

Consider the local isotropic functional family:

$$
\boxed{
\mathcal E_F(\psi)
=
\int
F(|\psi|)
dx,
}
\tag{7.1}
$$

whose variational gradient is:

$$
J_F(\psi)
=
g(|\psi|)\psi
$$

for some scalar:

$$
g.
$$

For the divergence-free transport:

$$
T_U,
$$

all such local functionals satisfy:

$$
\boxed{
\langle
T_U\psi,
J_F(\psi)
\rangle
=
0
}
\tag{7.2}
$$

as long as the chain rule is valid.

Now we demand a stronger condition:

> For all divergence-free $\psi$, $J_F(\psi)$ remains divergence-free.

We have:

$$
\operatorname{div}
(g(|\psi|)\psi)
=
g'(|\psi|)
\psi\cdot\nabla|\psi|.
$$

For this expression to be identically zero for all admissible divergence-free fields,

it must be that:

$$
\boxed{
g' = 0.
}
$$

Therefore:

$$
g=\text{constant}.
$$

That is:

$$
\boxed{
F(r)
=
cr^2/2
+
\text{constant}.
}
\tag{7.3}
$$

Thus, among local isotropic integral metrics:

$$
\boxed{
\textbf{
quadratic }L^2\textbf{ geometry is the unique universal geometry
that preserves both raw transport cancellation and divergence-free norm gradient}.
}
}
\tag{7.4}
$$

This is a restricted theorem.

It does not rule out nonlocal / nonlinear / relational critical functionals.

---

# 8. Critical Hilbert route: $\dot H^{-1/2}$

Now we switch to:

$$
A
=
\Lambda^{-1},
$$

where:

$$
\Lambda=(-\Delta)^{1/2}.
$$

Define:

$$
\boxed{
\|\psi\|_{\dot H^{-1/2}}^2
=
\langle
\psi,A\psi
\rangle.
}
\tag{8.1}
$$

Since:

$$
A
$$

is a scalar radial Fourier multiplier,

it commutes with:

$$
P.
$$

If:

$$
P\psi=\psi,
$$

then:

$$
P A\psi
=
A\psi.
$$

Therefore:

$$
\boxed{
\langle
P T_U\psi,
A\psi
\rangle
=
\langle
T_U\psi,
A\psi
\rangle.
}
\tag{8.2}
$$

Thus:

$$
\dot H^{-1/2}
$$

fully preserves projection compatibility.

---

# 9. Exact critical Hilbert commutator identity

From:

$$
T_U^\ast
=
-T_U
$$

in $L^2$,

we have:

$$
\boxed{
2
\langle
T_U\psi,
A\psi
\rangle
=
\langle
\psi,
[A,T_U]\psi
\rangle.
}
\tag{9.1}
$$

Therefore:

$$
\boxed{
\frac12
\frac d{d\sigma}
\|\psi\|_{\dot H^{-1/2}}^2
+
\nu
\|\psi\|_{\dot H^{1/2}}^2
=
\frac12
\left\langle
\psi,
[\Lambda^{-1},T_U]\psi
\right\rangle.
}
\tag{9.2}
$$

This is the exact critical Hilbert dual balance.

Thus:

$$
\boxed{
\dot H^{-1/2}
\text{ keeps Leray compatibility but loses exact transport skewness}.
}
\tag{9.3}
$$

The reason is not that the transport itself is not skew.

Rather, the critical metric:

$$
\Lambda^{-1}
$$

does not commute with the transport.

---

# 10. Fourier representation of the commutator defect

Let:

$$
k=p+q.
$$

Then:

$$
\widehat{T_U\psi}(k)
=
i
\int
\left(
q\cdot\widehat U(p)
\right)
\widehat\psi(q)
dp.
$$

Therefore:

$$
\boxed{
\widehat{
[\Lambda^{-1},T_U]\psi
}(k)
=
i
\int
\left(
|k|^{-1}
-
|q|^{-1}
\right)
\left(
q\cdot\widehat U(p)
\right)
\widehat\psi(q)
dp.
}
\tag{10.1}
$$

The critical defect is therefore a continuous triad weight-gap integral.

Moreover:

$$
\boxed{
\left|
|k|^{-1}
-
|q|^{-1}
\right|
=
\frac{
\left||
k|-|q|
\right|
}{
|k||q|
}
\le
\frac{
|p|
}{
|k||q|
}.
}
\tag{10.2}
$$

This is isomorphic to the no-free-radial-jump mechanism from Round 09.

---

# 11. General radial Hilbert metric

More generally, let:

$$
A=a(\Lambda)
$$

be a real radial self-adjoint multiplier.

Define:

$$
\mathcal E_a(\psi)
=
\frac12
\langle
\psi,A\psi
\rangle.
$$

Projection compatibility still holds.

The transport defect is:

$$
\boxed{
\frac12
\langle
\psi,
[A,T_U]\psi
\rangle.
}
\tag{11.1}
$$

The Fourier symbol is:

$$
\boxed{
a(|k|)
-
a(|q|).
}
\tag{11.2}
$$

So if:

$$
a
$$

is constant,

the commutator vanishes pointwise.

This is precisely $L^2$.

---

# 12. Restricted radial-Hilbert uniqueness

Suppose we require:

$$
\boxed{
\langle
\psi,
[A,T_U]\psi
\rangle
=
0
}
\tag{12.1}
$$

to hold for all smooth divergence-free:

$$
U,\psi.
$$

If:

$$
a
$$

is not constant,

we can choose a nondegenerate continuous Fourier triad:

$$
k=p+q
$$

such that:

$$
a(|k|)
\neq
a(|q|).
$$

Then choose divergence-free polarizations and relative phases such that:

$$
q\cdot\widehat U(p)\neq0
$$

and the corresponding quadratic commutator pairing is non-zero.

In $\mathbb R^3$, one can use smooth Fourier wave packets concentrated near this nondegenerate triad to realize the same symbol-level nonvanishing.

Therefore, universal exact cancellation forces:

$$
\boxed{
a(r)=\text{constant}.
}
\tag{12.2}
$$

Thus, among radial translation-invariant Hilbert metrics:

$$
\boxed{
\textbf{
}L^2\textbf{ is again the unique universal metric
with exact transport cancellation}.
}
\tag{12.3}
$$

This is likewise a restricted theorem.

---

# 13. Criticality–Cancellation Tradeoff

Now the two critical routes form a mirror image.

## Local critical geometry

$$
\boxed{
L^{3/2}
}
$$

preserves:

$$
\boxed{
\text{transport chain-rule cancellation}
}
$$

but loses:

$$
\boxed{
\text{projection compatibility}.
}
$$

## Hilbert critical geometry

$$
\boxed{
\dot H^{-1/2}
}
$$

preserves:

$$
\boxed{
\text{projection compatibility}
}
$$

but loses:

$$
\boxed{
\text{transport cancellation}
}
$$

Only:

$$
\boxed{
L^2
}
$$

preserves both simultaneously within the two tested natural metric families.

But for the dual NS scaling:

$$
\|\psi_\lambda\|_2
=
\lambda^{1/2}
\|\psi\|_2,
$$

so:

$$
\boxed{
L^2
\text{ is not scale-critical}.
}
$$

Therefore, we obtain the:

$$
\boxed{
\textbf{Criticality–Cancellation Tradeoff}.
}
\tag{13.1}
$$

---

# 14. Cancellation square

We can put the three spaces into a table.

| Dual geometry | scale critical | raw transport cancellation | Leray compatibility | defect |
|---|---:|---:|---:|---|
| $L^2$ | no | yes | yes | none |
| $L^{3/2}$ | yes | yes | no | $\mathfrak P_{3/2}$ |
| $\dot H^{-1/2}$ | yes | no | yes | commutator $\mathfrak C_{-1/2}$ |

where:

$$
\boxed{
\mathfrak C_{-1/2}[U,\psi]
=
\frac12
\langle
\psi,
[\Lambda^{-1},T_U]\psi
\rangle.
}
\tag{14.1}
$$

Thus, the critical dual obstruction is not a single issue of "insufficient estimates".

It consists of two distinct geometric defects.

---

# 15. Defect pair as a relational state

Define the critical dual defect pair:

$$
\boxed{
\mathfrak D_{\rm crit}
=
\left(
\mathfrak P_{3/2},
\mathfrak C_{-1/2}
\right).
}
\tag{15.1}
$$

These two defects respectively measure:

$$
\boxed{
\text{norm-gradient leakage out of divergence-free space}
}
$$

and:

$$
\boxed{
\text{critical metric failure to commute with transport}.
}
$$

Therefore, selecting only one scalar norm hides the other structure.

The observation state of this round naturally elevates again to:

$$
\boxed{
\mathsf X_{\rm dual}.
}
$$

---

# 16. A universal contraction would need both defects controlled

If one hopes to find a critical dual functional:

$$
\mathfrak N(\psi)
$$

such that:

$$
\boxed{
\frac d{d\sigma}
\mathfrak N(\psi)
\le0
}
$$

holds for an arbitrary smooth NS drift:

$$
U,
$$

its variational geometry must simultaneously handle at least:

1. diffusion coercivity;
2. divergence-free constraint;
3. transport invariance / skewness;
4. critical scaling.

In the two natural classes of this round:

$$
\boxed{
\text{critical scaling}
}
$$

and:

$$
\boxed{
\text{double exact cancellation}
}
$$

do not appear simultaneously.

Therefore, the next carrier cannot simply be:

$$
L^{3/2}
$$

or:

$$
\dot H^{-1/2}
$$

under a different name.

It must genuinely change the geometry.

---

# 17. Projection defect is a nonlinear tangent-space defect

For:

$$
L^{3/2},
$$

the norm gradient is:

$$
J_{3/2}(\psi)
=
|\psi|^{-1/2}\psi.
$$

Even if:

$$
\psi
$$

lies on the divergence-free manifold,

$$
J_{3/2}(\psi)
$$

generally does not remain divergence-free under its tangent-cotangent identification.

Therefore:

$$
P
$$

must be re-projected:

$$
J_{3/2}
\mapsto
P J_{3/2}.
$$

And the transport cancellation originally holds for:

$$
J_{3/2},
$$

not for:

$$
P J_{3/2}.
$$

Thus:

$$
\boxed{
\text{constraint projection}
}
$$

and:

$$
\boxed{
\text{local entropy gradient}
}
$$

do not commute.

The X-order representation is:

$$
\boxed{
P
\circ
J_{3/2}
\neq
J_{3/2}
\circ
P.
}
\tag{17.1}
$$

---

# 18. Hilbert defect is a metric–transport commutator

For:

$$
\dot H^{-1/2},
$$

the constraint projection has no issues.

But the critical metric is generated by:

$$
A=\Lambda^{-1}.
$$

The transport:

$$
T_U
$$

alters the frequency content.

Therefore:

$$
\boxed{
[A,T_U]
\neq0.
}
\tag{18.1}
$$

This is not a pressure defect.

Nor is it the norm gradient leaving the divergence-free space.

It is the noncommutativity between:

$$
\boxed{
\text{metric}
\leftrightarrow
\text{transport}
}
$$

.

---

# 19. Two noncommutativities

Thus, Round 12 found two exact X-order obstructions:

$$
\boxed{
\begin{aligned}
\text{Local critical:}\quad&
P J
\neq
J P,
\\
\text{Hilbert critical:}\quad&
A T
\neq
T A.
\end{aligned}
}
\tag{19.1}
$$

The uniqueness of $L^2$ lies in the fact that:

$$
J_2=I,
$$

$$
A_2=I,
$$

so both commutators simultaneously degenerate to zero.

---

# 20. Why a fixed combination does not automatically repair the problem

One might consider a composite functional:

$$
\mathfrak N
=
c_1
\|\psi\|_{3/2}^{3/2}
+
c_2
\|\psi\|_{\dot H^{-1/2}}^2.
$$

Its derivative will only yield:

$$
\boxed{
c_1
\mathfrak P_{3/2}
+
c_2
\mathfrak C_{-1/2}
}
$$

plus dissipations.

But currently, there is no identity forcing:

$$
\mathfrak P_{3/2}
$$

and:

$$
\mathfrak C_{-1/2}
$$

to cancel each other out.

Thus:

$$
\boxed{
\text{multi-norm addition}
\neq
\text{relational closure}.
}
\tag{20.1}
$$

What is truly needed is a new structural relation between the two defects.

---

# 21. A candidate critical geometric functional

This round naturally derives the next search target.

Do not pre-specify:

$$
L^p
$$

or:

$$
H^s.
$$

Instead, look for a functional:

$$
\boxed{
\mathfrak N_{\rm crit}[\psi]
}
$$

satisfying:

## C1. Critical homogeneity

$$
\boxed{
\mathfrak N_{\rm crit}[\psi_\lambda]
=
\mathfrak N_{\rm crit}[\psi].
}
$$

## C2. Constraint compatibility

Its variational gradient:

$$
J_{\rm crit}(\psi)
=
\frac{\delta\mathfrak N_{\rm crit}}{\delta\psi}
$$

is compatible with the Leray projection in the relevant dual pairing.

## C3. Transport cancellation or controlled commutator

$$
\boxed{
\langle
P T_U\psi,
J_{\rm crit}(\psi)
\rangle
\le
\text{coercive diffusion term}.
}
$$

## C4. Lossless norm detection

Controlling:

$$
\mathfrak N_{\rm crit}
$$

must be sufficient to control the primal critical continuation quantity.

This is a genuine geometric variational problem.

---

# 22. STOP-C16 — Criticality / Double-Cancellation Gap

Define:

$$
\boxed{
\bot_X^{\mathrm{C16}}
=
\left\langle
\begin{array}{l}
\text{layer}
=
\mathrm{critical\ dual\ geometry},
\\
L^{3/2}\text{ preserves}
=
\mathrm{transport\ chain\ rule},
\\
L^{3/2}\text{ loses}
=
\mathrm{Leray\ compatibility},
\\
\dot H^{-1/2}\text{ preserves}
=
\mathrm{Leray\ compatibility},
\\
\dot H^{-1/2}\text{ loses}
=
\mathrm{transport\ commutation},
\\
L^2\text{ preserves}
=
\mathrm{both},
\\
L^2\text{ critical}
=
\mathrm{false},
\\
\text{missing}
=
\mathrm{critical\ functional\ with\ joint\ cancellation/coercivity},
\\
\text{discrete\ intrusion}
=
\mathrm{false}.
\end{array}
\right\rangle.
}
$$

Name:

$$
\boxed{
\textbf{STOP-C16:
Criticality / Double-Cancellation Gap}.
}
$$

---

# 23. This is not a proof that no critical contractive geometry exists

The restricted no-go of this round only covers:

1. local isotropic integral metrics;
2. radial translation-invariant Hilbert multiplier metrics.

Thus, it cannot be deduced that:

$$
\boxed{
\text{no critical continuous dual Lyapunov functional exists}.
}
$$

There may still exist:

- nonlinear nonlocal functionals;
- quotient / constrained Finsler geometries;
- transport-adapted metrics;
- Lagrangian critical metrics;
- relational multi-carrier functionals;
- dynamically varying dual metrics.

Therefore, the Pure-C path is not yet sealed off.

---

# 24. 24/72 Ledger — Round 12

| Step | X object / operation | $B$ | $U$ | $O$ | $L$ | status |
|---|---|---|---|---|---|---|
| C124 | backward-time dual equation | $\mathsf C$ | $\mathsf S/\mathsf P$ | relational | $\mathsf F$ | EXACT |
| C125 | dual scaling | $\mathsf C$ | — | scalar | $\mathsf F$ | EXACT |
| C126 | $L^{3/2}$ critical route | $\mathsf C$ | local | scalar | $\mathsf F$ | FORM |
| C127 | raw $L^p$ transport cancellation | $\mathsf C$ | transport | scalar | $\mathsf F$ | EXACT |
| C128 | projection defect $\mathfrak P_{3/2}$ | $\mathsf C$ | constraint | relational | $\mathsf F$ | EXACT |
| C129 | local isotropic double-cancellation | $\mathsf C$ | — | local metric | $\mathsf F$ | ONLY QUADRATIC UNIVERSALLY |
| C130 | $\dot H^{-1/2}$ critical route | $\mathsf C$ | Hilbert/nonlocal | scalar | $\mathsf F$ | FORM |
| C131 | projection compatibility in $\dot H^{-1/2}$ | $\mathsf C$ | constraint | Hilbert | $\mathsf F$ | EXACT |
| C132 | commutator defect $\mathfrak C_{-1/2}$ | $\mathsf C$ | transport | relational | $\mathsf F$ | EXACT |
| C133 | radial Hilbert exact transport cancellation | $\mathsf C$ | — | multiplier metric | $\mathsf F$ | ONLY CONSTANT MULTIPLIER UNIVERSALLY |
| C134 | criticality–cancellation tradeoff | $\mathsf C$ | multi-route | $\mathsf X$ | $\mathsf F$ | PROVED IN TESTED CLASSES |
| C135 | universal critical double-cancellation functional | $\mathsf C$ | variational | $\mathsf X$ | $\mathsf F$ | OPEN / STOP-C16 |

---

# 25. Continuous-versus-discrete status

Round 12 introduced absolutely no:

- atomic decomposition;
- dyadic shell;
- wavelet index;
- discrete packet family;
- sequence extraction.

All defects are formed by continuous operators:

$$
P,
\quad
\Lambda^{-1},
\quad
T_U
$$

and variational gradients.

Therefore:

$$
\boxed{
T_{\mathsf C\to\mathsf D}
=
\text{NOT YET REACHED}.
}
\tag{25.1}
$$

---

# 26. Pure-C path after Round 12

$$
\boxed{
\begin{aligned}
\mathsf C_{\rm energy}
&\to
\mathsf C_{\rm critical}
\\
&\to
\mathsf C_{\rm relational}
\\
&\to
\mathsf C_{\rm nonlocal}
\\
&\to
\mathsf C_{\rm projected}
\\
&\to
\mathsf C_{\rm gradient\ geometry}
\\
&\to
\mathsf C_{\rm hierarchy}
\\
&\to
\mathsf C_{\rm Gevrey}
\\
&\to
\mathsf C_{\rm covariance}
\\
&\to
\mathsf C_{\rm triad\ phase}
\\
&\to
\mathsf C_{\rm phase\ network}
\\
&\to
\mathsf C_{\rm functional}
\\
&\to
\mathsf C_{\rm dual\ adjoint}
\\
&\to
\mathsf C_{\rm critical\ variational\ geometry}.
\end{aligned}
}
\tag{26.1}
$$

---

# 27. Strongest result of Round 12

The most important structural result of this round:

$$
\boxed{
\begin{array}{c|cc}
&\text{Transport cancellation}&\text{Leray compatibility}
\\
\hline
L^2&\checkmark&\checkmark
\\
L^{3/2}&\checkmark&\times
\\
\dot H^{-1/2}&\times&\checkmark
\end{array}
}
\tag{27.1}
$$

And:

$$
L^2
$$

does not possess dual critical scaling.

Therefore, among the two most natural classes of critical dual geometry:

$$
\boxed{
\textbf{
criticality splits the two exact cancellations
that coincide at }L^2.
}
}
\tag{27.2}
$$

---

# 28. Next round — projected critical entropy / constrained metric

The next round will no longer test more off-the-shelf norms.

It will directly attempt to construct:

$$
\boxed{
\mathfrak N_{\rm crit}[\psi]
}
$$

so that its gradient lives in the divergence-free constraint geometry from the very beginning.

Candidate paths:

1. constrained entropy gradient:

$$
J_{\rm div}
=
P J_{3/2};
$$

2. Check if there exists a functional:

$$
\mathfrak N
$$

such that:

$$
\frac{\delta\mathfrak N}{\delta\psi}
=
P J_{3/2}(\psi);
$$

3. If it does not exist, find the integrability obstruction:
   whether the projected entropy vector field is not a functional gradient;

4. If it exists, study the transport pairing:

$$
\langle
T_U\psi,
J_{\rm div}
\rangle;
$$

5. More generally, search for a critical constrained Finsler metric;

6. If all continuous constrained metrics require atomic / wave-packet decomposition to be defined or estimated, only then reconsider:

$$
T_{\mathsf C\to\mathsf D}.
$$

This round will directly ask a very specific variational question:

$$
\boxed{
\textbf{
Can Leray projection of the critical entropy gradient itself be integrated
back into a scalar critical functional?
}
}
$$

---

# 29. External primary-source anchors

1. Dong Li, *On Kato-Ponce and fractional Leibniz*, arXiv:1609.01780.
   - fractional Leibniz / commutator estimates;
   - The standard analytical background for the transport–multiplier commutator encountered in the $\dot H^{-1/2}$ route of this round.

2. D. Q. Khai, N. M. Tri, *On the initial value problem for the Navier-Stokes equations with the initial datum in critical Sobolev and Besov spaces*, arXiv:1601.01726.
   - Navier–Stokes local theory and small-data global framework in critical homogeneous Sobolev spaces.

3. Jean-Yves Chemin, Ping Zhang, *On the critical one component regularity for 3-D Navier-Stokes system*, arXiv:1310.6442.
   - $\dot H^{1/2}$ scaling-critical Navier–Stokes regularity framework.

The projection-defect identity, critical Hilbert commutator identity, two restricted uniqueness results, and the cancellation-tradeoff in this round are all directly derived in this document.

---

# 30. Commit state

$$
\boxed{
\begin{aligned}
\text{Route}
&:
\mathrm{Pure\ Continuous\ Critical\ Dual\ Geometry},
\\
\text{Essential }\mathsf C\to\mathsf D
&:
\mathrm{Not\ reached},
\\
L^{3/2}\text{ defect}
&:
\mathfrak P_{3/2},
\\
\dot H^{-1/2}\text{ defect}
&:
\mathfrak C_{-1/2},
\\
L^2\text{ double cancellation}
&:
\mathrm{exact},
\\
L^2\text{ criticality}
&:
\mathrm{false},
\\
\text{Restricted natural critical classes}
&:
\mathrm{no\ double\ exact\ cancellation},
\\
\text{STOP-C16}
&:
\mathrm{Criticality/Double\text{-}Cancellation\ Gap},
\\
\text{Next}
&:
\mathrm{Projected\ Critical\ Entropy/Constrained\ Metric}.
\end{aligned}
}
$$