> Full-text translation from Chinese. The original remains authoritative for its research claims; this translation is not independent mathematical verification.

# SRBRD-01
## Structural Compression Audit
### Exact Cell Cardinalities, Center-Divisor Collapse, CRT Overlap, Tree-Overlap Upper Bound and First-Order No-Go

**Parent program:** RG-SCP / Reverse Goldbach Structural Closure Program  
**Branch:** SRBRD — Symmetric Root-Bounded Relation Domain  
**Round:** SRBRD-01  
**Date:** 2026-09-30  
**Version:** v0.1  
**Authors:** Neo.K; Aletheia (GPT-5.6 Sol)  
**Type:** Exact Structural Audit / Compression Test / Non-Coverage Infrastructure  
**Prerequisite:** SRBRD-00 Exact Representation Kernel  
**Status:** Nontrivial exact compression found; a global non-cover theorem has not yet been obtained

---

# 0. Aim of This Round

SRBRD-00 has established the candidate exact representation:

$$
\boxed{
|\operatorname{Res}(m)|
=
R_G^{-}(2m)
}
$$

and:

$$
\boxed{
\operatorname{GoldbachFailure}(2m)
\Longleftrightarrow
\Omega_m
=
\bigcup_{\sigma,r}
O_{m,\sigma,r}.
}
$$

SRBRD-01 no longer discusses the equivalence itself.

This round asks only:

> Do root-truncated residue cells have additional structure absent from a general finite cover, sufficient to produce proof compression?

This round obtains four core exact results:

1. Left and right cells have exact cofactor parameterizations;
2. Cell cardinalities can be counted in closed form;
3. The left and right cells of the same prime undergo residue collapse if and only if $r\mid m$;
4. Intersections for distinct primes are compressed by CRT into a single parity-lifted residue class.

It further establishes:

$$
\boxed{
\text{Tree-Overlap Upper Bound}
}
$$

turning pairwise CRT overlap into an actual union upper bound.

But the computational audit also shows that:

$$
\boxed{
\text{first-order cell capacity}
}
$$

and:

$$
\boxed{
\text{pairwise tree-overlap alone}
}
$$

are both insufficient to achieve the global Goldbach closure currently in view.

Thus the verdict of this round is:

$$
\boxed{
\text{NONTRIVIAL COMPRESSION FOUND}
}
$$

However:

$$
\boxed{
\text{GLOBAL NON-COVER NOT YET CLOSED}.
}
$$

---

# 1. Offset Domain Cardinality

Retain:

$$
\Omega_m
=
\left\{
d\in\mathbb N:
d\le m-3,
\quad
m-d\text{ odd}
\right\}.
$$

## Theorem SRBRD-01-T01

For:

$$
m\ge3,
$$

we have:

$$
\boxed{
|\Omega_m|
=
\left\lfloor
\frac{m-1}{2}
\right\rfloor.
}
$$

Since:

- If $m$ is odd, admissible $d$ are even:
  $$
  0,2,\ldots,m-3;
  $$
- If $m$ is even, admissible $d$ are odd:
  $$
  1,3,\ldots,m-3.
  $$

---

# 2. Left Cell Reparameterization

SRBRD-00：

$$
O_{L,r}
=
\left\{
d\in\Omega_m:
r\mid(m-d),
\quad
r^2\le m-d
\right\}.
$$

Let:

$$
m-d=kr.
$$

Since:

- $m-d$ is odd;
- $r$ is an odd prime;

Thus:

$$
\boxed{
k\text{ odd}.
}
$$

root bound：

$$
r^2\le kr
$$

is equivalent to:

$$
\boxed{
r\le k.
}
$$

And:

$$
d\ge0
$$

is equivalent to:

$$
kr\le m.
$$

That is:

$$
k\le
\left\lfloor
\frac mr
\right\rfloor.
$$

Thus:

## Theorem SRBRD-01-T02

$$
\boxed{
O_{L,r}
=
\left\{
m-kr:
k\text{ odd},
\quad
r\le k\le
\left\lfloor
\frac mr
\right\rfloor
\right\}.
}
$$

---

# 3. Left Cell Immediate Consequence

If:

$$
r^2>m,
$$

then:

$$
\left\lfloor
\frac mr
\right\rfloor<r.
$$

Thus:

$$
\boxed{
O_{L,r}=\varnothing.
}
$$

Therefore:

$$
\boxed{
r^2>m
\Longrightarrow
\text{$r$ is right-only}.
}
$$

This rewrites the root-asymmetry of SRBRD-00 as an exact factor/cofactor interval.

---

# 4. Right Cell Reparameterization

SRBRD-00：

$$
O_{R,r}
=
\left\{
d\in\Omega_m:
r\mid(m+d),
\quad
r^2\le m+d
\right\}.
$$

Let:

$$
m+d=kr.
$$

Likewise, since the endpoint is odd:

$$
\boxed{
k\text{ odd}.
}
$$

From:

$$
d\ge0
$$

we obtain:

$$
kr\ge m,
$$

That is:

$$
k\ge
\left\lceil
\frac mr
\right\rceil.
$$

From the root bound:

$$
r^2\le kr
$$

we obtain:

$$
k\ge r.
$$

And:

$$
d\le m-3
$$

is equivalent to:

$$
kr-m\le m-3,
$$

That is:

$$
k\le
\left\lfloor
\frac{2m-3}{r}
\right\rfloor.
$$

Thus:

## Theorem SRBRD-01-T03

$$
\boxed{
O_{R,r}
=
\left\{
kr-m:
k\text{ odd},
\quad
\max
\left(
r,
\left\lceil
\frac mr
\right\rceil
\right)
\le k
\le
\left\lfloor
\frac{2m-3}{r}
\right\rfloor
\right\}.
}
$$

---

# 5. Odd-Interval Counting Function

Define:

$$
\boxed{
\operatorname{OddCount}(a,b)
=
\#\{k\in\mathbb N:a\le k\le b,\ k\text{ odd}\}.
}
$$

For:

$$
a\le b,
$$

we have:

$$
\boxed{
\operatorname{OddCount}(a,b)
=
\left\lfloor
\frac{b+1}{2}
\right\rfloor
-
\left\lfloor
\frac a2
\right\rfloor.
}
$$

If:

$$
a>b,
$$

Define:

$$
\operatorname{OddCount}(a,b)=0.
$$

---

# 6. Exact Left Cell Cardinality

From T02:

## Theorem SRBRD-01-T04

$$
\boxed{
|O_{L,r}|
=
\operatorname{OddCount}
\left(
r,
\left\lfloor
\frac mr
\right\rfloor
\right).
}
$$

This formula automatically covers the cell being empty when:

$$
r^2>m
$$

holds.

---

# 7. Exact Right Cell Cardinality

From T03:

## Theorem SRBRD-01-T05

$$
\boxed{
|O_{R,r}|
=
\operatorname{OddCount}
\left(
\max
\left(
r,
\left\lceil
\frac mr
\right\rceil
\right),
\left\lfloor
\frac{2m-3}{r}
\right\rfloor
\right).
}
$$

---

# 8. Small / Large Witness Regimes

Define:

$$
Q_m^{\mathrm{small}}
=
\{r:r^2\le m\},
$$

$$
Q_m^{\mathrm{large}}
=
\{r:m<r^2\le2m-3\}.
$$

---

# 9. Small Witness Simplification

If:

$$
r^2\le m,
$$

then:

$$
\frac mr\ge r.
$$

Thus:

$$
\left\lceil
\frac mr
\right\rceil
\ge r.
$$

the right lower bound simplifies to:

$$
\boxed{
k\ge
\left\lceil
\frac mr
\right\rceil.
}
$$

That is, for a small witness:

- Central-to-left factor states exist on the left side;
- The root bound on the right side is already satisfied by $m+d\ge m\ge r^2$.

---

# 10. Large Witness Simplification

If:

$$
m<r^2\le2m-3,
$$

then:

$$
O_{L,r}=\varnothing.
$$

and:

$$
\left\lceil
\frac mr
\right\rceil<r
$$

or at least does not exceed the root lower requirement,

so the right lower bound is governed by:

$$
\boxed{
k\ge r
}
$$

as displayed above.

A large witness starts only from the right frontier.

---

# 11. Root-Availability Monotonicity

Define:

$$
Q_L(m,d)
=
\{r:r^2\le m-d\},
$$

$$
Q_R(m,d)
=
\{r:r^2\le m+d\}.
$$

If:

$$
d_1\le d_2,
$$

then:

$$
\boxed{
Q_L(m,d_2)
\subseteq
Q_L(m,d_1)
}
$$

while:

$$
\boxed{
Q_R(m,d_1)
\subseteq
Q_R(m,d_2).
}
$$

Thus, as the offset moves to the right:

> Left root-witness availability monotonically shrinks, while right root-witness availability monotonically expands.

This is an entirely target-independent exact frontier law.

---

# 12. Same-Prime Residue Collision

For the same odd prime:

$$
r,
$$

left residue：

$$
d\equiv m\pmod r,
$$

right residue：

$$
d\equiv-m\pmod r.
$$

the two residue classes are identical if and only if:

$$
m\equiv-m\pmod r,
$$

that is:

$$
2m\equiv0\pmod r.
$$

Since:

$$
r
$$

is an odd prime,

Thus:

## Theorem SRBRD-01-T06

$$
\boxed{
m\equiv-m\pmod r
\Longleftrightarrow
r\mid m.
}
$$

---

# 13. Center-Divisor Collapse

## Theorem SRBRD-01-T07

If:

$$
r\mid m,
$$

then:

$$
\boxed{
O_{L,r}\subseteq O_{R,r}.
}
$$

Proof:

If:

$$
d\in O_{L,r},
$$

then:

$$
r\mid(m-d).
$$

Also:

$$
r\mid m,
$$

Thus:

$$
r\mid d.
$$

Therefore:

$$
r\mid(m+d).
$$

and the left root bound:

$$
r^2\le m-d
$$

immediately implies:

$$
r^2\le m+d.
$$

Hence:

$$
d\in O_{R,r}.
$$

---

# 14. Non-Center Prime Side Disjointness

## Theorem SRBRD-01-T08

If:

$$
r\nmid m,
$$

then:

$$
\boxed{
O_{L,r}\cap O_{R,r}
=
\varnothing.
}
$$

For if:

$$
d
$$

belongs to both sides,

then:

$$
r\mid(m-d),
$$

$$
r\mid(m+d).
$$

Thus:

$$
r\mid2m.
$$

since $r$ is odd:

$$
r\mid m,
$$

a contradiction.

---

# 15. Exact Same-Prime Union Cardinality

Let:

$$
P_{m,r}
=
O_{L,r}\cup O_{R,r}.
$$

then:

## Theorem SRBRD-01-T09

If:

$$
r\mid m,
$$

then:

$$
\boxed{
|P_{m,r}|
=
|O_{R,r}|.
}
$$

If:

$$
r\nmid m,
$$

then:

$$
\boxed{
|P_{m,r}|
=
|O_{L,r}|
+
|O_{R,r}|.
}
$$

---

# 16. Center Compression Term

Define the raw side capacity:

$$
\boxed{
S_{\mathrm{raw}}(m)
=
\sum_r
\left(
|O_{L,r}|
+
|O_{R,r}|
\right).
}
$$

Define the same-prime collapsed capacity:

$$
\boxed{
S_{\mathrm{prime}}(m)
=
\sum_r
|P_{m,r}|.
}
$$

From T07/T08:

$$
\boxed{
S_{\mathrm{raw}}(m)
-
S_{\mathrm{prime}}(m)
=
\sum_{\substack{
r\mid m\\
r\in Q_m
}}
|O_{L,r}|.
}
$$

This is an exact, target-independent compression term.

---

# 17. The First Genuinely New Source of Compression

This means:

> The prime divisors of the center $m$ are not merely obstruction sources; they also force the left and right obstruction channels to coincide.

Thus:

$$
\boxed{
r\mid m
}
$$

simultaneously provides:

1. A divisibility source;
2. A same-prime overlap source.

This has a spirit similar to divisor self-suppression in RG-SCP, but acts on the new symmetric offset relation domain.

---

# 18. Different-Prime CRT Intersection

Consider:

$$
r\neq s
$$

two odd primes,

and:

$$
\sigma,\tau\in\{L,R\}.
$$

Each side cell has a residue:

$$
d\equiv\epsilon_\sigma m\pmod r,
$$

$$
d\equiv\epsilon_\tau m\pmod s,
$$

where:

$$
\epsilon_L=+1,
\qquad
\epsilon_R=-1.
$$

Since:

$$
\gcd(r,s)=1,
$$

CRT gives a unique residue class modulo:

$$
rs.
$$

---

# 19. Parity Lift

$\Omega_m$ also requires:

$$
m-d
$$

to be odd.

That is:

$$
d
$$

to have a fixed parity.

Since:

$$
2,r,s
$$

are pairwise coprime,

CRT again gives:

## Theorem SRBRD-01-T10

For:

$$
r\neq s,
$$

and any side pair:

$$
(\sigma,\tau),
$$

if the intersection:

$$
O_{\sigma,r}\cap O_{\tau,s}
$$

is nonempty,

then all its elements lie in:

$$
\boxed{
\text{a unique residue class modulo }2rs.
}
$$

---

# 20. Interval Part of Pairwise Intersection

Each side-prime cell also has an interval:

### Left

$$
I_{L,r}
=
[0,m-r^2].
$$

If:

$$
r^2>m,
$$

then it is empty.

### Right

$$
I_{R,r}
=
[\max(0,r^2-m),m-3].
$$

Thus:

$$
O_{\sigma,r}\cap O_{\tau,s}
$$

is precisely:

$$
\boxed{
\text{one residue class mod }2rs
\cap
I_{\sigma,r}
\cap
I_{\tau,s}
\cap
\Omega_m.
}
$$

Once parity is absorbed into the residue modulo $2rs$, it need not be counted separately.

---

# 21. Exact Pairwise Intersection Count Interface

Define:

$$
\operatorname{APCount}(a,b;q,c)
$$

to be the number of integers in:

$$
[a,b]
$$

that satisfy:

$$
d\equiv c\pmod q
$$

the displayed congruence.

Then, for distinct primes:

$$
r,s,
$$

we have:

$$
\boxed{
|O_{\sigma,r}\cap O_{\tau,s}|
=
\operatorname{APCount}
\left(
a_{\sigma,\tau},
b_{\sigma,\tau};
2rs,
c_{\sigma,\tau}
\right),
}
$$

where:

- $a_{\sigma,\tau}$ is the maximum of the two interval lower bounds;
- $b_{\sigma,\tau}$ is the minimum of the upper bounds;
- $c_{\sigma,\tau}$ is uniquely determined by CRT.

Thus pairwise overlap itself is entirely exact, finite and target-independent.

---

# 22. Prime-Grouped Cells

Formally take the union of the left and right sides of the same prime first:

$$
\boxed{
P_{m,r}
=
O_{L,r}\cup O_{R,r}.
}
$$

Then the Goldbach obstruction union is:

$$
\boxed{
\mathcal O_m
=
\bigcup_r P_{m,r}.
}
$$

This is more natural than treating $L/R$ as two independent cells,

because T07/T08 already give the exact same-prime structure.

---

# 23. Cross-Prime Overlap Surplus

Define:

$$
\boxed{
X_m
=
\sum_r|P_{m,r}|
-
\left|
\bigcup_rP_{m,r}
\right|.
}
$$

From the union cardinality:

$$
\boxed{
|\operatorname{Res}(m)|
=
|\Omega_m|
-
S_{\mathrm{prime}}(m)
+
X_m.
}
$$

This is the SRBRD version of the overlap identity.

---

# 24. Data Role of Exact $X_m$

Since:

$$
|\operatorname{Res}(m)|
=
|\Omega_m|-S_{\mathrm{prime}}+X_m,
$$

the exact quantity:

$$
X_m
$$

is highly coupled to residual truth.

Thus the exact $X_m$ is a:

$$
\boxed{
\text{truth-adjacent diagnostic}.
}
$$

The actual proof input should be a:

$$
\boxed{
\text{a lower bound obtained without reading residual truth, on }X_m.
}
$$

---

# 25. Tree-Overlap Upper Bound

This round finds a particularly clean finite-set theorem.

Consider all nonempty prime-grouped cells:

$$
P_1,\ldots,P_t.
$$

Take a spanning tree connecting these cell indices:

$$
T.
$$

then:

## Theorem SRBRD-01-T11

$$
\boxed{
\left|
\bigcup_{i=1}^{t}P_i
\right|
\le
\sum_{i=1}^{t}|P_i|
-
\sum_{(i,j)\in E(T)}
|P_i\cap P_j|.
}
$$

---

# 26. T11 Proof Idea

Root the tree at an arbitrary $P_1$.

Add each child in turn:

$$
P_j.
$$

The number of elements it adds is at most:

$$
|P_j|
-
|P_j\cap P_{\operatorname{parent}(j)}|.
$$

Summing over all vertices gives the result.

This theorem requires only elementary finite-set arithmetic.

---

# 27. Maximum-Overlap Tree

To obtain the strongest tree correction,

take the edge weight:

$$
w(r,s)
=
|P_{m,r}\cap P_{m,s}|.
$$

Choose a maximum spanning tree:

$$
T_m^{\max}.
$$

Define:

$$
\boxed{
X_m^{\mathrm{tree}}
=
\sum_{(r,s)\in E(T_m^{\max})}
|P_{m,r}\cap P_{m,s}|.
}
$$

then:

$$
\boxed{
X_m\ge X_m^{\mathrm{tree}}.
}
$$

---

# 28. Tree Structural Upper Bound

Therefore:

$$
\boxed{
\left|
\bigcup_rP_{m,r}
\right|
\le
S_{\mathrm{prime}}(m)
-
X_m^{\mathrm{tree}}.
}
$$

Thus the residual lower bound is:

$$
\boxed{
|\operatorname{Res}(m)|
\ge
|\Omega_m|
-
S_{\mathrm{prime}}(m)
+
X_m^{\mathrm{tree}}.
}
$$

---

# 29. Tree Non-Cover Criterion

## Theorem SRBRD-01-T12

If:

$$
\boxed{
S_{\mathrm{prime}}(m)
-
X_m^{\mathrm{tree}}
<
|\Omega_m|,
}
$$

then:

$$
\boxed{
\operatorname{Res}(m)\neq\varnothing.
}
$$

Therefore:

$$
\boxed{
R_G^{-}(2m)>0.
}
$$

This is a genuine finite structural certificate that does not directly test endpoint primality.

---

# 30. Why This Is More Suitable than Simple Pairwise Inclusion-Exclusion

The ordinary second-order Bonferroni expression:

$$
S_1-S_2
$$

provides a union lower bound,

not the upper bound we need.

The tree bound selects only a set of pairwise overlaps,

but guarantees a:

$$
\boxed{
\text{union upper bound}.
}
$$

It can therefore directly serve a:

$$
\text{non-cover proof}.
$$

---

# 31. First-Order Capacity Criterion

At the coarsest level:

$$
\left|
\bigcup_rP_{m,r}
\right|
\le
S_{\mathrm{prime}}(m).
$$

If:

$$
S_{\mathrm{prime}}(m)<|\Omega_m|,
$$

this proves a residual exists.

This is the first-order criterion.

---

# 32. First-Order No-Go

But it cannot serve as the current universal closure engine.

A single exact control suffices:

$$
m=100.
$$

we have:

$$
|\Omega_{100}|=49,
$$

$$
S_{\mathrm{raw}}(100)=67,
$$

$$
S_{\mathrm{prime}}(100)=59.
$$

Therefore:

$$
S_{\mathrm{prime}}(100)>|\Omega_{100}|.
$$

Thus:

$$
\boxed{
\text{same-prime collapse alone cannot prove the case }m=100.
}
$$

But the actual obstruction union is:

$$
\left|
\bigcup_rP_{100,r}
\right|
=
41.
$$

Thus the residual is:

$$
8.
$$

This means:

$$
\boxed{
\text{cross-prime overlap is necessary information.}
}
$$

---

# 33. $m=100$ Cell Audit

witness primes：

$$
3,5,7,11,13.
$$

cell cardinalities：

### $r=3$

$$
|O_{L,3}|=16,
$$

$$
|O_{R,3}|=16.
$$

Since:

$$
3\nmid100,
$$

the two sides are disjoint:

$$
|P_{100,3}|=32.
$$

### $r=5$

$$
|O_{L,5}|=8,
$$

$$
|O_{R,5}|=10.
$$

Since:

$$
5\mid100,
$$

$$
O_{L,5}\subseteq O_{R,5},
$$

Thus:

$$
|P_{100,5}|=10.
$$

### $r=7$

$$
|P_{100,7}|=4+7=11.
$$

### $r=11$

large witness：

$$
|O_{L,11}|=0,
$$

$$
|O_{R,11}|=4.
$$

### $r=13$

$$
|O_{L,13}|=0,
$$

$$
|O_{R,13}|=2.
$$

Thus:

$$
S_{\mathrm{prime}}=32+10+11+4+2=59.
$$

---

# 34. $m=100$ Tree Compression

The pairwise CRT overlaps can construct a maximum-overlap tree,

whose total correction is:

$$
X_{100}^{\mathrm{tree}}=17.
$$

Therefore:

$$
\left|
\bigcup_rP_{100,r}
\right|
\le
59-17
=
42.
$$

And:

$$
42<49=|\Omega_{100}|.
$$

the tree criterion can already prove:

$$
\boxed{
|\operatorname{Res}(100)|\ge7.
}
$$

In fact:

$$
|\operatorname{Res}(100)|=8.
$$

That is, the tree lower bound differs from the exact value by only $1$.

This is a very strong finite control.

---

# 35. $m=210$: Center-Rich Case

Computational exact audit:

$$
|\Omega_{210}|=104,
$$

$$
S_{\mathrm{prime}}(210)=101.
$$

In fact, the first-order criterion already directly gives:

$$
101<104.
$$

Thus a residual can be proved without cross-prime correction.

Adding the maximum tree overlap:

$$
X_{210}^{\mathrm{tree}}=21,
$$

we obtain:

$$
|\cup P_r|
\le80.
$$

Thus:

$$
|\operatorname{Res}(210)|\ge24.
$$

Actual residual:

$$
30.
$$

The center $210$ has several small prime divisors,

so same-prime collapse is itself very strong.

---

# 36. $m=211$: Center-Prime Contrast

$$
211
$$

is itself prime.

Thus there is almost no center-divisor same-prime collapse.

Computational audit:

$$
|\Omega_{211}|=105,
$$

$$
S_{\mathrm{prime}}(211)=166.
$$

The first-order criterion fails completely.

But the maximum tree overlap is:

$$
X_{211}^{\mathrm{tree}}=62.
$$

Thus:

$$
|\cup P_r|
\le104.
$$

And:

$$
104<105.
$$

the tree overlap still proves:

$$
\boxed{
|\operatorname{Res}(211)|\ge1.
}
$$

Actual residual:

$$
11.
$$

This shows that cross-prime CRT overlap is powerful not only for composite centers.

---

# 37. The Pairwise Tree Bound Is Still Not Universal

For example:

$$
m=1000.
$$

Computational audit:

$$
|\Omega_{1000}|=499,
$$

$$
S_{\mathrm{prime}}(1000)=908,
$$

Maximum tree correction:

$$
381.
$$

Thus the tree upper bound is:

$$
527.
$$

However:

$$
527>499.
$$

Therefore the tree criterion cannot prove a residual exists.

There are still, in fact, this many residuals:

$$
37.
$$

Thus:

$$
\boxed{
\text{pairwise tree overlap is still insufficient for universal closure}.
}
$$

---

# 38. Larger Control

For:

$$
m=5000,
$$

Computational audit:

$$
|\Omega_m|=2499,
$$

$$
S_{\mathrm{prime}}=5495,
$$

Tree correction:

$$
2554,
$$

Tree upper bound:

$$
2941,
$$

Still:

$$
2941>2499.
$$

While the actual residual is:

$$
127.
$$

Thus higher-order redundancy remains large, but the pairwise tree captures only part of it.

---

# 39. Computational Sanity Scan

This round uses finite direct enumeration for a non-proof sanity audit.

Range:

$$
3\le m\le5000.
$$

Checks:

1. left cofactor cardinality formula；
2. right cofactor cardinality formula；
3. If $r\mid m$:
   $$
   O_{L,r}\subseteq O_{R,r};
   $$
4. If $r\nmid m$:
   $$
   O_{L,r}\cap O_{R,r}=\varnothing.
   $$

Result:

$$
\boxed{
\text{0 mismatches in the scanned range}.
}
$$

This is only computational evidence,

not a formal proof.

---

# 40. Tree Criterion Scan

In the same:

$$
3\le m\le5000
$$

scan,

the maximum spanning-tree criterion:

$$
S_{\mathrm{prime}}-X^{tree}
<
|\Omega_m|
$$

succeeds for:

$$
366
$$

values of $m$.

Within this range:

- The first failure occurs at:
  $$
  m=199;
  $$
- Isolated successes still occur afterward;
- The last success in this scan is:
  $$
  m=1155.
  $$

This again shows:

$$
\boxed{
\text{tree overlap provides real compression, but not global closure.}
}
$$

---

# 41. Compression Hierarchy

The following can currently be established:

## Layer 0 — Raw Sides

$$
S_{\mathrm{raw}}
=
\sum_r
\left(
|L_r|+|R_r|
\right).
$$

## Layer 1 — Same-Prime Collapse

$$
S_{\mathrm{prime}}
=
\sum_r
|L_r\cup R_r|.
$$

## Layer 2 — Pairwise Tree Correction

$$
U_{\mathrm{tree}}
=
S_{\mathrm{prime}}
-
X^{tree}.
$$

## Layer 3 — Exact Union

$$
U_{\mathrm{exact}}
=
\left|
\bigcup_rP_r
\right|.
$$

we have:

$$
\boxed{
U_{\mathrm{exact}}
\le
U_{\mathrm{tree}}
\le
S_{\mathrm{prime}}
\le
S_{\mathrm{raw}}.
}
$$

---

# 42. Residual Lower-Bound Hierarchy

Correspondingly:

$$
|\operatorname{Res}(m)|
=
|\Omega_m|-U_{\mathrm{exact}}.
$$

we obtain:

$$
\boxed{
|\operatorname{Res}(m)|
\ge
|\Omega_m|-U_{\mathrm{tree}}.
}
$$

A weaker bound is:

$$
\ge
|\Omega_m|-S_{\mathrm{prime}}.
$$

As long as any lower bound is:

$$
>0,
$$

it proves Goldbach success for the fixed $m$.

---

# 43. The Structural Question That Actually Remains

It is now very clear.

To move toward a uniform theorem,

a lower bound is needed on:

$$
\boxed{
X_m
}
$$

that is, cross-prime redundancy,

but without directly calculating the exact union.

Possible subjects of study are:

1. tree overlap；
2. higher-order overlap；
3. forced repeated coverage；
4. residue-product constraints；
5. root-frontier coupling；
6. center-divisor induced overlap；
7. endpoint factorization multiplicity；
8. A global closure invariant.

---

# 44. CRT Pairwise Overlap Is a Legitimate Proof Input

Importantly:

$$
|P_{m,r}\cap P_{m,s}|
$$

can be calculated entirely from:

- $m$;
- $r,s$;
- Residues;
- Root intervals;

as displayed above.

It does not require asking whether:

$$
m\pm d
$$

is prime.

Thus pairwise CRT overlap is a:

$$
\boxed{
\text{proof-admissible structural input}.
}
$$

---

# 45. Exact Residual / Exact Union, by Contrast, Is a Truth Label

By contrast:

$$
|\operatorname{Res}(m)|
$$

is directly equal to:

$$
R_G^{-}(2m).
$$

Thus:

$$
\boxed{
\text{TruthLabel}.
}
$$

Likewise, the exact total overlap:

$$
X_m
$$

combined with:

$$
S_{\mathrm{prime}}
$$

can reconstruct the residual,

and is therefore truth-adjacent.

---

# 46. The Next Reasonable Target

It is not to continue adding more pairwise counting.

The next round should ask:

> Is there a **higher-order overlap lower bound** that still depends only on truncated residue geometry?

Specific candidates:

### A. CRT Hyperedge Closure

The joint intersection of three or more primes.

### B. Occupancy Multiplicity Lower Bound

Directly prove that many covered offsets must be repeatedly covered by multiple primes.

### C. Root-Frontier Conservation

Does the shrinkage of left witness availability together with right expansion force overlap?

### D. Center-Class Stratification

Stratify into families according to:

$$
\gcd(m,P(y))
$$

or the prime factors of the center.

### E. Factor-Cofactor Duality

The cell parameter:

$$
m\pm d=kr
$$

contains the condition:

$$
k\ge r
$$

Can this form a new involution / pairing?

---

# 47. Cofactor Duality Is Especially Worth Examining

left：

$$
m-d=kr,
$$

right：

$$
m+d=kr.
$$

All obstruction cells on both sides can be regarded as:

$$
\boxed{
\text{odd factor }r
+
\text{odd cofactor }k
+
k\ge r.
}
$$

Thus the relation is not just a residue sieve.

It is actually a:

$$
\boxed{
(r,k,d)
}
$$

ternary finite relation.

This may be closer than a simple CRT union to the next genuinely new structure.

---

# 48. Formal Theorem Queue

```yaml
SRBRD_01:
  T01: omega_cardinality
  T02: left_cell_cofactor_parameterization
  T03: right_cell_cofactor_parameterization
  T04: left_cell_exact_cardinality
  T05: right_cell_exact_cardinality
  T06: same_prime_residue_collision_iff_r_dvd_m
  T07: center_divisor_left_subset_right
  T08: noncenter_same_prime_side_disjoint
  T09: same_prime_union_cardinality
  T10: distinct_prime_intersection_single_class_mod_2rs
  T11: tree_overlap_union_upper_bound
  T12: tree_overlap_noncover_criterion
```

---

# 49. Acceptance Gate

Before SRBRD-01 can be promoted to a formal core, it requires:

1. exact OddCount formula；
2. left cofactor bijection；
3. right cofactor bijection；
4. small/large regime theorem；
5. same-prime collision iff $r\mid m$；
6. center-divisor subset theorem；
7. noncenter disjoint theorem；
8. distinct-prime CRT intersection theorem；
9. pairwise intersection exact AP-count interface；
10. tree union upper-bound proof；
11. tree residual lower bound；
12. first-order no-go control；
13. Separation of computational evidence from theorem statements;
14. No claim of global Goldbach closure.

---

# 50. Verdict

This round can reach a stronger judgment than SRBRD-00:

$$
\boxed{
\mathrm{SRBRD\mbox{-}01\ STRUCTURAL\ COMPRESSION\ PASS}
}
$$

because it has indeed found exact restrictions beyond linguistic recoding:

- cofactor interval；
- right-only large-witness regime；
- center-divisor same-prime collapse；
- parity-lifted CRT intersections；
- tree-overlap non-cover certificate。

However:

$$
\boxed{
\mathrm{GLOBAL\ NONCOVER\ GATE\ NOT\ PASSED}.
}
$$

In particular, finite controls such as:

$$
m=1000,
5000
$$

have already proved that:

> Same-prime compression and pairwise tree correction remain insufficient for universal closure.

---

# 51. Recommendations for the Next Round

# SRBRD-02
## Higher-Order Overlap / Cofactor Closure Audit

Priorities:

1. Promote the $(r,k)$ cofactor parameterization to the primary relation;
2. Study forced overlap among multiple factor edges of the same endpoint;
3. Establish ternary CRT hyperintersections;
4. Search for an occupancy lower bound;
5. Seek a bound independent of exact residual truth:
   $$
   X_m\ge L_X(m);
   $$
6. Attempt the closure:
   $$
   |\Omega_m|
   -
   S_{\mathrm{prime}}(m)
   +
   L_X(m)
   >0.
   $$

If this layer still yields no uniform gain,

then assess whether SRBRD encounters the traditional sieve overlap / parity barrier.

---

# Appendix A: Machine-Oriented Definitions

```text
OddCount(a,b)
LeftCell(m,r)
RightCell(m,r)
PrimeCell(m,r) = LeftCell union RightCell
CenterCompression(m)
PairIntersection(m,r,s)
TreeOverlap(m,T)
TreeUnionUpper(m,T)
```

---

# Appendix B: Selected Audit Table

| $m$ | $|\Omega_m|$ | $S_{\mathrm{prime}}$ | Tree overlap | Tree union upper | Exact union | Exact residual |
|---:|---:|---:|---:|---:|---:|---:|
| 34 | 16 | 17 | 3 | 14 | 14 | 2 |
| 50 | 24 | 24 | 6 | 18 | 18 | 6 |
| 100 | 49 | 59 | 17 | 42 | 41 | 8 |
| 199 | 99 | 155 | 56 | 99 | 92 | 7 |
| 210 | 104 | 101 | 21 | 80 | 74 | 30 |
| 211 | 105 | 166 | 62 | 104 | 94 | 11 |
| 1000 | 499 | 908 | 381 | 527 | 462 | 37 |
| 5000 | 2499 | 5495 | 2554 | 2941 | 2372 | 127 |

**Note:** Exact union / Exact residual serve only as truth-channel audits and must not be used to construct a proof bound.

---

# Appendix C: Source / Data Role

```yaml
SRBRD_01:
  exact_structural_inputs:
    - center_m
    - witness_prime_r
    - cofactor_interval
    - congruence
    - root_truncation
    - CRT_pair_intersection

  proof_admissible:
    - exact_cell_cardinality
    - center_divisor_collapse
    - pairwise_CRT_overlap
    - tree_overlap_lower_correction

  truth_labels:
    - exact_residual
    - exact_union

  truth_adjacent:
    - exact_total_overlap_surplus
```

---

# Appendix D: Commit Decision

```yaml
research_round: SRBRD-01

decision:
  exact_reencoding_only: false
  nontrivial_structural_compression: true
  global_noncover_proved: false

new_exact_structures:
  - left_cofactor_parameterization
  - right_cofactor_parameterization
  - same_prime_center_divisor_collapse
  - distinct_prime_mod_2rs_intersections
  - maximum_spanning_tree_overlap_bound

negative_results:
  - first_order_capacity_not_universal
  - pairwise_tree_bound_not_universal

next:
  SRBRD-02_HigherOrder_Overlap_Cofactor_Closure_Audit
```
